Integrand size = 8, antiderivative size = 67 \[ \int \sinh \left (a+b x^n\right ) \, dx=-\frac {e^a x \left (-b x^n\right )^{-1/n} \Gamma \left (\frac {1}{n},-b x^n\right )}{2 n}+\frac {e^{-a} x \left (b x^n\right )^{-1/n} \Gamma \left (\frac {1}{n},b x^n\right )}{2 n} \]
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Time = 0.01 (sec) , antiderivative size = 67, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {5414, 2239} \[ \int \sinh \left (a+b x^n\right ) \, dx=\frac {e^{-a} x \left (b x^n\right )^{-1/n} \Gamma \left (\frac {1}{n},b x^n\right )}{2 n}-\frac {e^a x \left (-b x^n\right )^{-1/n} \Gamma \left (\frac {1}{n},-b x^n\right )}{2 n} \]
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Rule 2239
Rule 5414
Rubi steps \begin{align*} \text {integral}& = -\left (\frac {1}{2} \int e^{-a-b x^n} \, dx\right )+\frac {1}{2} \int e^{a+b x^n} \, dx \\ & = -\frac {e^a x \left (-b x^n\right )^{-1/n} \Gamma \left (\frac {1}{n},-b x^n\right )}{2 n}+\frac {e^{-a} x \left (b x^n\right )^{-1/n} \Gamma \left (\frac {1}{n},b x^n\right )}{2 n} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.94 \[ \int \sinh \left (a+b x^n\right ) \, dx=-\frac {e^a x \left (-b x^n\right )^{-1/n} \Gamma \left (\frac {1}{n},-b x^n\right )-e^{-a} x \left (b x^n\right )^{-1/n} \Gamma \left (\frac {1}{n},b x^n\right )}{2 n} \]
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Result contains higher order function than in optimal. Order 5 vs. order 4.
Time = 0.45 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.10
method | result | size |
meijerg | \(x \operatorname {hypergeom}\left (\left [\frac {1}{2 n}\right ], \left [\frac {1}{2}, 1+\frac {1}{2 n}\right ], \frac {x^{2 n} b^{2}}{4}\right ) \sinh \left (a \right )+\frac {x^{n +1} b \operatorname {hypergeom}\left (\left [\frac {1}{2}+\frac {1}{2 n}\right ], \left [\frac {3}{2}, \frac {3}{2}+\frac {1}{2 n}\right ], \frac {x^{2 n} b^{2}}{4}\right ) \cosh \left (a \right )}{n +1}\) | \(74\) |
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\[ \int \sinh \left (a+b x^n\right ) \, dx=\int { \sinh \left (b x^{n} + a\right ) \,d x } \]
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\[ \int \sinh \left (a+b x^n\right ) \, dx=\int \sinh {\left (a + b x^{n} \right )}\, dx \]
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none
Time = 0.09 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.91 \[ \int \sinh \left (a+b x^n\right ) \, dx=\frac {x e^{\left (-a\right )} \Gamma \left (\frac {1}{n}, b x^{n}\right )}{2 \, \left (b x^{n}\right )^{\left (\frac {1}{n}\right )} n} - \frac {x e^{a} \Gamma \left (\frac {1}{n}, -b x^{n}\right )}{2 \, \left (-b x^{n}\right )^{\left (\frac {1}{n}\right )} n} \]
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\[ \int \sinh \left (a+b x^n\right ) \, dx=\int { \sinh \left (b x^{n} + a\right ) \,d x } \]
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Timed out. \[ \int \sinh \left (a+b x^n\right ) \, dx=\int \mathrm {sinh}\left (a+b\,x^n\right ) \,d x \]
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